The icosahedral point group
But there is more one can do. With the command Cases[Symmetry["I"], {{_, _, _}, 2 p/3, 1}][[1, 1]] one obtains one of the 3fold symmetry axis of the point group. Using this axis as the Miller index input to the MakeCrystal command produces a polyhedron with faces perpendicular to the 3fold symmetry axes of the group. Thus, ShowCrystal[{Cases[Symmetry["I"], {{_, _, _}, 2 p/3, 1}][[1, 1]]}, "I"] yields:


